0=4x^2+30x+56

Solution for 0=4x^2+30x+56 equation:

0=4x^2+30x+56

We move all terms to the left:

0-(4x^2+30x+56)=0

We add all the numbers together, and all the variables

-(4x^2+30x+56)=0

We get rid of parentheses

-4x^2-30x-56=0

a = -4; b = -30; c = -56;
Δ = b2-4ac
Δ = -302-4·(-4)·(-56)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2}{2*-4}=\frac{28}{-8}
=-3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2}{2*-4}=\frac{32}{-8}
=-4
$